Question

10) A force of 5N
acts on a body of mass 2 kg for 4 seconds. Assuring the body to
be initially atrest. Find (1) Its velocity when force stops acting (b) the distance
covered in 10 sec after the force starts acting.​

Answer 1

Answer:

1) v= (f/m)t

v = (5/ 2)4

v= 10 m/s

2) s = 1/2 (f/m) t²

s= 1/2 (5/2) 100

s = 125 m