Question

10 A hemispherical bowl is made of steel 0.25 cm
thick. The inside radius of the bowl is 5 cm. Find
the volume of steel used in making the bowl.
plz tell the ans in step by step​

Answer 1

Answer:

I hope this is correct ans

and this will help u to solve

Answer 2

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

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• Thickness of bowl = 0.25 cm
• inner bowl = 5cm

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$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

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• Volume of steel used to make the bowl = ??

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$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

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inner radius = 5cm

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outer radius = inner radius + thickness

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outer radius = 5cm + 0.25cm = 5.25cm

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$\sf{\red{\boxed{\bold{volume = \dfrac{2}{3}\times \pi \times[(outer\: radius)^3 - ( inner\: radius)^3] }}}}$

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$\sf : \implies\: {\bold{ volume = \dfrac{2}{3}\times \dfrac{22}{7}\times[ ( 5.25)^3 - (5)^3]}}$

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$\sf : \implies\: {\bold{ volume = \dfrac{2}{3}\times \dfrac{22}{7}\times[ 144.7 - 125]}}$

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$\sf : \implies\: {\bold{ volume = \dfrac{2}{3}\times \dfrac{22}{7}\times[ 19.7 ]}}$

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$\sf : \implies\: {\bold{ volume = \dfrac{44}{21}\times 19.7 }}$

$\sf : \implies\: {\bold{ volume = \dfrac{866.8}{21}}}$

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$\sf : \implies\: {\bold{ volume = 41.28 cm^3}}$

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$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

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• 41.28cm³ steel is required to make the bowl