Question

*10. A Horizontal force of 600 N pulls two masses 10 kg and 20 kg lying on a frictionless table
and connected by a light string. What is the tension in the string? Does the answer depend on
which mass end the pull is applied ?​

Answer 1

Answer:

in ur que....tenson will be 590.....

tenson = larger force - smaller force .....in your case...

Answer 2

Answer:

ExplanationGiven,

Mass of body (m1) = 10 Kg

Mass of body (m2) = 20 Kg

Horizontal force F = 600 N

Let a is the acceleration of system

(A) when force F applied on A:

use free body diagram ,

For body m1 ,

F - T = m1a ______________(1)

For body m2 ,

T = m2a ___________(2)

Solve eqns (1) and (2)

a = F/(m1 + m2)

= 600/(10 + 20)

= 20 m/s²

And T = m2a = 20×20 = 400 N

(B) again, using free body diagram when force on B

For body m1 ,

T = m1a _____________(1)

For body B,

F - T = m2a ___________(2)

Solve eqns (1) and (2)

a = F/(m1 + m2)

= 600/(10+20)

= 30 m/s²

And T = 10×20 = 200 N