Question

10. A lever of length 100cm has the effort of 50kgf at a distance of 40cm from the fulcrum which is at one end of the lever. What load may be applied at its other end?
pls explain

Answer 1

Answer:

so as lever= 100 cm

effort arm= 40 cm

load arm= 60 cm

effort=15kg

so here x/15=40/60

that is:; 10/15=40/60

how: 15*4= 60

. so x*4=40

. now x= 40/4=10kg

solved

Explanation:

hope it helps.