Question

10. A man reared cows and buffaloes. The
number of buffaloes was 7 more than
one-third of the number of cows. What
was the total number of animals, if the
number of buffaloes was 21?​

Answer 1

Step-by-step explanation:

hope the answer helps you

Answer 2

${\huge{\boxed{\underline{\textsf{\textbf{\color{pink}{Final\:An}{\pink{sw}{\purple{er:-}}}}}}}}}$

$\boxed{\implies 42}$

$\huge\underbrace\red{\dag Given:- \dag}$

A man reared cows and buffaloes

number of buffaloes was 7 more than one-third of the number of cows

the number of buffaloes was 21

$\huge\underbrace\pink {\dag To Find:- \dag}$

the total number of animals

$\huge\underbrace\purple{\dag Solution:- \dag}$

let the total number of animal be x

the number of buffaloes was 21

number of buffaloes was 7 more than one-third of the number of cows

now let's frame the equation

$21=7+\frac{1}{3} x$

$21=7+\frac{x}{3}$

$21=\frac{21+x}{3}$

$21+x=21 \times 3$

$21+x=63$

$x=63-21$

$x=42$

hence the total number of animals $\boxed{\implies 42}$