10. A particle moves a distance x in time t
according to equation x = (t + 5)-1. The
acceleration of particle is proportional to
(a) (velocity)3/2 (b) (distance)2
(c) (distance)-2 (d) (velocity)2/3
(2010)
Answers
Answered by
4
Answer:
distance x=(t+5)−1
x
=
(
t
+
5
)
−
1
velocity v=dxdt
v
=
d
x
d
t
=−(t+5)−2
=
−
(
t
+
5
)
−
2
acceleration a=dvdt
a
=
d
v
d
t
=2(t+5)−3
=
2
(
t
+
5
)
−
3
Therefore v3/2=−(t+5)−3
v
3
/
2
=
−
(
t
+
5
)
−
3
Therefore a=−2v3/2
a
=
−
2
v
3
/
2
aαv3/2
a
α
v
3
/
2
Hence a is the correct answer.
Answered by
6
Answer:
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