Question

10) A particle of 10 kg is moving in a constant acceleration 2m/s2 starting from rest. Calculate its momentum and velocity for t=2 sec.

Answer 1

Answer:

Mass = 10kg

Initial Velocity(u) = 0m/s

Final Velocity(v) = ?

Acceleration(a) = 2m/$s^{2}$

We know that,

v = u + at

v = 0 + (2m/$s^{2}$ x 2s)

v = 0 +  ( 4m/s)

v = 4m/s

The velocity is 4m/s.

Now let's find Momentum(p)/

Momentum (p) = Mass(m) x Velocity (v)

Momentum (p) = 10kg x 4m/s

Momentum (p) = 40kg m/s

Therefore the momentum for the object is  40kg m/s.

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Answer 2

Explanation:

U=0(initial velocity)

v=?

a=2m/s2

using 1St equation of motion

v=u+at

v=0(2m/s2*2s)

v=4m/s

find momentum

p=mass*velocity

p=10kg*4m/s

p=40kg m/s