Question

10. A particle of mass 2 kg, executing SHM has amplitude 20 cm and time period 1 s. Its maximum speed is
(1) 0.314 m/s
(2) 0.628 m/s
(3) 1.256 m/s
(4) 2.512 m/s​

Answer 1

Explanation:

Given A particle of mass 2 kg, executing SHM has amplitude 20 cm and time period 1 s. Its maximum speed is

• Given m = 2 kg, A = 20 cm = 0.2 m, T = 1 s
• We know that angular velocity ω = 2π / T
• Maximum velocity in simple harmonic motion is given by
• We know that V max = Aω
•                                  = 20 cm x 2π / T
•                                 = 0.2 m x 2 π / 1 (since 20 / 100 = 0.2 m)
•                               = 0.2 x 2 x 3.14
•                               = 1.256 m / s

Therefore maximum speed of the particle is 1.256 m/s

Reference link will be

https://brainly.in/question/7688564