10. A particle travels with an initial velocity of +6.0 m/s and moves with an acceleration of -2.0 m/s
. Calculate the displacement of the particle after 5 seconds?
Answers
Given:
- Initial velocity of particle, u = +6 m/s
- Acceleration of particle, a = -2 m/s²
- Time for which it travel, t = 5 sec
To find:
- Displacement of the particle, s =?
Formula required:
- Second equation of motion
s = u t + 1/2 a t²
[ Where s is displacement, u is initial velocity, t is time taken, a is acceleration ]
Calculation:
Using second equation of motion
→ s = u t + 1/2 a t²
→ s = ( 6 ) ( 5 ) + 1/2 ( -2 ) ( 5 )²
→ s = 30 - ( 5 )²
→ s = 30 - 25
→ s = 5 metres
Therefore,
- Displacement of particle would be 5 metres .
Three equations of motion:
- First equation of motion
v = u + a t
- Second equation of motion
s = u t + 1/2 a t²
- Third equation of motion
2 a s = v² - u²
[ Where v is final velocity, u is initial velocity, a is acceleration, t is time taken and s is displacement ]
Answer:
✡ Given ✡
A particle travels with an initial velocity of 6 m/s and moves with an acceleration of -2 m/s.
✡ To Find ✡
What is the displacement of the particle after 5 second.
✡ Formula Used ✡
✴ s = ut + at² ✴
✡ Solution ✡
Given:-
- u = 6 m/s
- t = 5 second
- a = -2 m/s²
▶ According to the question by using the formula we get,
s = (6).(5) + (-2).(5)²
s = (30) - (5)²
s = 30 - 25
s = 5 metres
The displacement of the particle after 5 second is 5 metres.
______________________
✡ Additional Information ✡
➡ There are three equation of motion :-
⭐ First equation of motion ⭐
v = u + at
⭐ Second equation of motion ⭐
v² = u² + 2as
⭐ Third equation of motion ⭐
s = ut + at²
where,
- s = displacement
- u = initial velocity
- v = final velocity
- a = acceleration
- t = time taken
Note:- These equation are reffered as SUVAT equation where SUVAT stands for,
- s = displacement
- u = initial velocity
- v = final velocity
- a = acceleration
- t = time taken
Explanation: