Question

10. A play school is designing two sand pits in
its play area. Each must have an area of
36 m2. However, one of the sand pits must be
rectangular, and the other must be square
shaped. What might be the dimensions of
each of the sand pits?
please solve the question and give anwer step by step​

Answer 1

Answer:

Dimensions of square shaped pit = 6m \times× 6m

Dimensions of rectangular pit = 1m \times× 36m or 2m \times× 18m or 3m \times× 12m or 4m \times× 9m

Step-by-step explanation:

Given:

Two pits in the school playground area (one square shaped and one rectangular shaped).

Each pit must have an area = 36 m^2m

2

To find:

Dimensions of each pit = ?

Solution:

First of all, let us have a look at the formula for area of a square and a rectangle:

Area_{square} = (Side)^2Area

square

=(Side)

2

Area_{Rectangle} = Length\times WidthArea

Rectangle

=Length×Width

Now, let us try to find out dimensions of square:

\begin{gathered}36 = Side^2\\\Rightarrow Side = 6\ m\end{gathered}

36=Side

2

⇒Side=6 m

So, dimensions of Square will be 6m \times× 6m.

Now, let us try to find out dimensions of rectangle.

36 = Length\times Width36=Length×Width

We are not given any restrictions on the Length and Width of the rectangle.

So, let us explore all the possibilities by factorizing 36:

\begin{gathered}36 = 1 \times 36\\36 = 2 \times 18\\36 = 3 \times 12\\36 = 4 \times 9\end{gathered}

36=1×36

36=2×18

36=3×12

36=4×9

6 \times× 6 factors not considered because then it will become a square and which is not the required case.

Dimensions of rectangular pit = 1m \times× 36m or 2m \times× 18m or 3m \times× 12m or 4m \times× 9m