Question

10. A rectangular field is 16 ½
m long and 12 ⅖
m wide. Find the perim
​

Answer 1

Given that,

Length of the field is 16 1/2

Width of the field is 12 2/5

Perimeter=2(l+b)

                 = 2(33/2+62/5)

                 = 2[{(5 x 33)+(2 x 62)}/10]

                 = 2([165+124]/10]          (Here 2 gets cancelled with 10)

                 = 289/5

                 = 57.5    

$hope \: this \: will \: help \: u$

Answer 2

Answer:

hii...

yr answer...

Perimeter = 2 (l+b)

=> Preimeter = 2 (33/2 + 62/5)

=> Perimeter = 2 × 165 + 124/ 10

=> Perimeter = 289/5

=> Perimeter = 57.8

..

THANKYOU