Math, asked by himakshi3354, 1 month ago

10. A rectangular piece of land is to be fenced for an exhibition. The length of the exhibition land
is 250 m and its breadth is 200 m. We need to keep an entrance of 10 m and an emergency
exit of 5 m. If the cost of this special fencing is 175 per metre, what will be the total cost
of fencing?​

Answers

Answered by TheDiamondBoyy
48

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  • Total cost would be Rs. 154.875

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Since we have given that

Length of exhibition land = 250 m

Breadth of exhibition land = 200 m

Entrance length = 10 m

Emergency exit length = 5 m

So, first perimeter of exhibition land is given by

= 2 × (250+200)

=2 × 450

=900 m

fencing removed for entrance = 900-10 = 890 m

Fencing removed for emergency exit = 890 - 5 =885 m

cost of fencing = Rs. 175 per meter

So, Total cost for total fencing is given by

\begin{gathered}175\times 885\\\\=Rs.\ 154.875\end{gathered}

=175×885

=Rs. 154.875

Hence, the total cost would be Rs.154.875

Answered by Anonymous
4

Answer:

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Since we have given that

Length of exhibition land = 250 m

Breadth of exhibition land = 200 m

Entrance length = 10 m

Emergency exit length = 5 m

So, first perimeter of exhibition land is given by

= 2 × (250+200)

=2 × 450

=900 m

fencing removed for entrance = 900-10 = 890 m

Fencing removed for emergency exit = 890 - 5 =885 m

cost of fencing = Rs. 175 per meter

So, Total cost for total fencing is given by

\begin{gathered}175\times 885\\\\=Rs.\ 154.875\end{gathered}

=175×885

=Rs. 154.875

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