10. A rope is (11x+7) cm long. A length of (2x - 5) cm is cut from it. Find the length of the remaining
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Answer:
Given,
length of wire =(7x−3)m
and wire cut for use has length =(3x−4)m
Left wire =(7x−3)−(3x−4)=(4x+1)m
(b) Left wire =(4x+1)m
Perimeter of equilateral triangle = Length of wire left
⇒ 3×side=4x+1
⇒ side= 3
(4x+1)
= 3
(4x+1)m
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