Question

10) A's present age in years is 20% of B's age. After
30 years, A's age will be 1/2 of B's. The sum of the present
ages of A and B is
Ad 40 years
B) 60 years
C) 80 years
D) 100 years​

Answer 1

Step-by-step explanation:

Let B's age = x

Since A's age is 20% of B

Therefore

A's age = 20% of x

= 20x/100

= x/5 years

Age of B after 30 years

x+30

Since after 30 years A's age = 1/2 of B' s age

Therefore A's age = 1/2 × x/30

= x/30

Now we need to find original age of A after 30 years

A's age after 30 years = x/5 + 30

= (x + 150)/5

Therefore the equation is

(x+30)/2 = (x + 150)/5

Cross multiplying we get

5x + 150 = 2x + 300

3x = 150

x = 50

Therefore B's age = 50 years

A's age = x/5

= 50/5

= 10 years

Sum of the ages of A and B = 50 + 10

= 60

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