Question

10. A silver ingot is 70 cm long, 50 cm wide, and 10 cm
high. If it is melted and is to be recast as small cubical
paperweights 5 cm long, how many paperweights can
be made from it?​

Answer 1

Answer:

Volume of steel ingot=  70*50*10

                                    = 35000 $cm^{3}$

Volume of paperweight= 5*5*5

                                       = 125  $cm^{3}$

Let n be the number of paperweights.

n*volume of paperweight= Volume of steel ingot

n*125= 35000

n=35000/125

n=280

Hence, 280 paperweights can be formed

Answer 2

Answer:

700

Step-by-step explanation:

Please mark my answer as brainlist answer..

No. Of cubical paperweights formed=volume of cuboidal ingot/volume of cubical paperweights

=l*b*h/side*sode*side

=70*50*10/5*5*5

=35000/125

=280 cubical paperweights