Question

10. A stone of mass m is thrown vertically upwards.
Another stone of mass 2m is thrown at an angle
theta with vertical. Both of them stay in air for same
period of time. The heights attained by the two
stones are in the ratio
(1) 1:1
(2) 2:1
(3) 1 : cos theta
(4) cos theta : 1​

Answer 1

Answer:

v

1

cosθ=v

0

Now,we also know 2gs=v

2

−u

2

From this,we derive:− \textgreater

s

0

=

2g

v

0

2

s

1

=

2g

v

1

2

cos

2

θ

Hence,the ratio is

s

0

s

1

=

2g

v

0

2

2g

v

1

2

cos

2

θ

=

v

0

2

v

1

2

cos

2

θ