10. A sum becomes 715 times itself in three years at
simple interest. Find the rate of interest.
(A) 1323% p.a.
(B) 12213% p.a.
(C) 13/3% p.a.
(D) 12/3% p.a.
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Answer:
let p =100
amount= 71500
therefore Interest =71500-100=71400
using SI formula
SI =P*T*R/100
71400=100*3*R/100
71400*100=300R
R=7140000/300
R=23800%
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