Question

10. A table top is 2.5 m long and 1.6 m wide. Find the cost of polishing it at the rate of ₹5 per M2


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Answer 1

Answer:

Rs.20

Step-by-step explanation:

____________________

Given,

Length = 2.5m

Breadth = 1.6m

Rate = Rs.5/m^2

Area to be painted = l × b

= 2.5 × 1.6

= 4m^2

Hence, Total Cost = 5 × 4 = Rs.20

Answer 2

Given :

• Length of the table top = 2.5 m
• Breadth of the table top = 1.6 m
• Rate of polishing it = Rs. 5

To find :

• Cost of polishing the table top at the rate of Rs. 5

Concept Used :

To find the cost of polishing the table top :-

• Firstly, find the area of the table top by using the formula of area of rectangle.
• Then multiply the area by the rate the resultant value will be our required answer.

Formula of area of rectangle :-

$\boxed{ \sf\pmb{ \blue{Area \: \: of \: \: rectangle \: = l \times b }}}$

Where,

• l = length
• b = breadth

Solution :

Area of the table top :-

$\\ \dashrightarrow\sf \quad{Area \: \: of \: \: table \: \: top = l \times b }$

$\\ \dashrightarrow\sf \quad{Area \: \: of \: \: table \: top = 2.5 \times 1.6 }$

$\\ \dashrightarrow\sf \quad{Area \: \: of \: \: table \: top = 4}$

$\\ \dag\sf \tt \red{\quad{Area \: \: of \: \: rectangle \: = 4 \: m^2}}$

Cost of polishing the table top = Area × Rate

$\\ \dashrightarrow \sf \quad \: Cost = 4 \times 5$

$\\ \dashrightarrow \sf \quad \: Cost = Rs. 20$

$\boxed{ \sf\pmb{ \blue{Cost \: \: of \: \: polishing \: \: the \: \: table \: \: top = Rs. 20}}}$

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Know More :

Some related formulae :-

• Perimeter of reactangle = 2(l + b)
• Diagonal of rectangle = √l² + √b²
• Area of square = side × side
• Perimeter of square = 4 × side
• Diagonal of square = √2a

Properties of rectangle :-

• The opposite sides of rectangle are equal to each other.
• The opposite side of rectangle are parallel to each other.
• The diagonals bisect each other.
• The sum of interior angles of rectangle sums upto 360°.