Physics, asked by AchintyaSharma, 8 months ago

10. A train is moving on straight track with velocity
Vo = 13.5 ms. To stop the train at a particular station,
the driver applies brakes at t = 0, which is caused of a
retardation proportional to the velocity of the train. The
speed of train reduces 50% in the first to = 4 In(2)s. Find
velocity of train (in msl) at t= 4 s. (Given, e = 2.7)​

Answers

Answered by MysteriousAryan
0

Answer:

11th

Physics

Motion in a Straight Line

Graphs in Relative Motion

The driver of a train movin...

PHYSICS

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Asked on December 27, 2019 by

Poulomi Tehreem

The driver of a train moving with a constant speed v

1

along a straight track sights another train at a distance d ahead of him on the same track moving in the same direction with a constant speed v

2

. He at once applies the brakes and gives his train a constant retardation f. There will be a collision of the trains if:

HARD

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ANSWER

Relative velocity v

12

=v

1

−v

2

,

Relative separation s

12

=d,

Relative acceleration a

12

=a

1

−a

2

=−f

Let at time t , trains collides.

Using s=ut+

2

1

at

2

⇒d=(v

1

−v

2

)t−

2

1

ft

2

⇒ft

2

−2(v

1

−v

2

)t+2d=0,

For real solution of t, (2(v

1

−v

2

))

2

−4×f×2d>0

2f

(v

1

−v

2

)

2

>d

∴ For collision v

1

>v

2

and

2f

(v

1

−v

2

)

2

>d

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