Math, asked by sarthakpandey6538, 1 year ago

10) a wall clock loses 10 minutes every 1 hour. In 1 hour by the wall clock , a table clock gets 10 minutes ahead of it. In 1 hour by the table clock an alarm clock falls 5 minutes behind it. In 1 hour of the alarm clock, a wristwatch gets 5 minutes ahead it. At noon, all 4 timepieces were set correctly. To the nearest minutes, what time will the wrist show when the correct time is 6 p.M. On the same day ?

Answers

Answered by joannaruth2102
1

Answer:

wrist show 6 pm on the same day

Step-by-step explanation:

Slightly confusing

The table clock is on time because after 1 hour wall clock lost 10 minutes and the table clock is 10 minutes ahead.

The alarm clock loses 5 minutes from real time so after 1 hour in alarm clock the real time is:

60 + 5*60/55 = 60 + 60/11 = 60*12/11

The wrist watch is 5 minutes ahead of alarm clock so its

60*12/11 - 65 minutes behind. = 5/11 minutes behind the real time.

So in 6 hours the wrist watch is 6*5/11 minutes behind.

To nearest minute, the wrist watch will show

5.57pm10 years agoHelpfull: Yes(2) No(6)wall clock = 10 min loses in 1 hour

table clock = 10 min ahead of wall clock that's means it's showing right time

now

alarm clock =5 min falls behind table clock

wristwatch=5 min ahead of alarm clock that's means it will show right time

we seen that wristwatch showing the right time so wrist show 6 pm on the same day

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