10. A well is dug out whose radius is 4.2 m and depth is 38
m. The earth taken out from well is spread all over a
rectangular field whose dimensions are 130 m x 115 m.
Find the rise in the level of field.
Answers
Answered by
26
The rise in the level of field is 0.1409 m (approx.)
Given data :
Radius of the well is 4.2m.
Depth of the well is 38 m.
Dimensions of the field is 130m×115m.
So,
Volume of the well = {π×(4.2)²×38}m² = {(22/7)×4.2×4.2×38}m² = 2106.72 m²
Let the rise of the field = h
So,
130×115×h = 2106.72
14950×h = 2106.72
h = 2106.72/14950 = 0.1409 m (approx) (answer)
Answered by
15
hey mate !!!! this is your answer.....
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