Question

10. A wire is of length 264 cm. It is bent into a circle. What is the radius of the circle so obtained. If it
is bent in the form of a square, find the side of the square.​

Answer 1

Step-by-step explanation:

circumference of circle=length of wire

=>2πr=264

=>2*22/7*r=264

=>r=264*7/2*22=42cm

now,

perimeter of square=length of wire

=>4a=264

=>a=264/4=66cm

Answer 2

Answer:

10. A wire is of length 264 cm. It is bent into a circle. What is the radius of the circle so obtained. If it

is bent in the form of a square, find the side of the square.

Step-by-step explanation:

Radius of the circle obtained: ≈42cm .

Side of the square formed: 66cm .

Solution:

Since the wire is bent in the form of a circle, length of wire is now the circumference of the circle.

If r is the radius of the circle, we can establish the relationship between circumference of circle and length of wire as: 2πr=264

Using the approximation of π=227 , we can compute radius to be:

r=264∗72∗22=42

If the wire is bent in the shape of a square, perimeter of the square is equal to the length of the wire.

If a is the length of the side of the square, we can establish the relationship between perimeter of square and length of wire as:

4a=264

So,

a=264/4=66