Question

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10.A wire of given material having length l and area of cross-section A has a resistance of 4 omega.
What would be the resistance of another wire of same material having length l ÷2 - and area of
cross-section 2A?​

Answer 1

Answer:

please refer the above attachment

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Answer 2

GIVEN - R=4ohm

As we know R=rho×l/A

so by this formula

R=Rho × l/2 / 2A

R= Rho × l / 4A

so if we compare it by By the formula it's is 1/4 of the formula so Resistance will also be 1/4

So the answer would be 4/4 = 1

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