Math, asked by TheBigBrainer, 2 months ago

10: AB is a chord of a circle with centre O. OP is a radius of the circle and is drawn parallel to AB. A is joined to O and AO is produced to meet the circle again at C. Prove that PC = PB.

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Answered by yogeshvts00007
0

Answer:

OA/OC =PB/PC

Step-by-step explanation:

when ab || op than oa/ob = pb/pc

than we know OA= OB THEN PB=PC

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