10. ABCD is a diameter of a circle of radius 6 cm.The length AB, BC and CD are equal.les are drawn on AB and BD as diameters as shown in the given figure. The shaded region of the area is found.
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area of shaded region= area of Semicircle AB + (AD-BD)
=π2×2+(π6×6-π4×4)=4π+(36π-16π)=4π+20π
=24πcm^2
=π2×2+(π6×6-π4×4)=4π+(36π-16π)=4π+20π
=24πcm^2
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