Math, asked by guptasweety135, 5 months ago

10. ABCD is a square and AC is one of its diagonals.
Prove that AABC = ACDA.
(Hint: Use SSS congruence criterion to prove AABC = ACDA]​

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Answered by abhiacharya7770
11

Step-by-step explanation:

ABCD is a square where AC is diagonal

so all the sides of square are equal

AC=AC (Same side)

BC=AD(sides are equal in square )

DC=AB(sides are equal in square)

so

Ans. triangle(ABC) is congregant to triangle (CDA)

hence proved

I hope this answer will help you ......

Answered by subhankardash531
17

Answer:

AB = CD

BC = DA

AC = AC

(COMMON SIDE)

SO ∆ABC CONGRUENTS TO ∆CDA (SSS)

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