Question

10. ABCD is a trapezium in which
AB || DC. If ar(AABD) = 24
cm² and AB = 8 cm, then
height of AABC is​

Answer 1

Answer:

Height of ∆ABC = 6cm

Step-by-step explanation:

Given:–

• ABCD is a trapezium

• AB || DC

• Area of ∆ADB = 24 cm^2

• AB = 8cm

To find: Height of ∆ABC

Solution:– We know that,

Two triangles with the same base and between the same parallels are equal in area.

So,

∆ADB and ∆ACB are on the same base AB

Hence,

Area of ∆ACB = Area of ∆ADB

∆ACB = 24

1/2 ( 8 x h ) = 24

( 8 x h ) = 24 x 2

8 x h = 48

h = 48/8

h = 6cm

Hence the height of ∆ABC = 6cm

Hope you like

Mark me as brainliest