Question

10. ABD is a diameter of acide of radiem. The AB
Cand CD are equal Semicides A and ND
diameters as shown in the given figure. Find the of desde
region (Take - 3.14)​

Answer 1

Step-by-step explanation:

Since, Length of AB, BC and CD are equal.

Radius of circle =6cm

Now, AD=2×6=12cm

⇒AB+BC+CD=12

⇒3AB=12

⇒AB=

3

12

⇒AB=4cm

⇒AB=BC=CD=4cm

Radius of semicircle AB=2cm

Radius of semicircle BC=4cm

Radius of semicircle AD=6cm

Area of the shaded region = Area of semicircle (AB+AD) − Area of semicircle (BD)

⇒ Area of shaded region =0.5π(2

2

+6

2

)−0.5π(4)

2

⇒ Area of shaded region =0.6π(4+36)−0.5π×16

⇒ Area of shaded region =20π−8π

⇒ Area of shaded region =12πcm

2