10. AC and BD are two perpendicular diameters of
a circle as shown in the figure. If the area of the
shaded part is 616 cm?, calculate
(a) the length of AC and
(b) the circumference of the circle.
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a) (AC/2)=(BD/2) - is radius
So, Area of triangle = pi * r(radius)^2
Area of triangle =616 cm square
Therefore, 616 = pi * r^2
616/pi= r^2
616/(22/7)
=(616*7)/22=28*7=196
r^2 = 196
( AD/2)^2=196
(AD^2)/4=196
AD = Sq. root of (196*4)
AD = Sq. root of (784)
So,AD = 28 cm
b) circumference of circle = pi * AD
So, 28 * pi
=28* 22/7
=4 * 22
= 88 cm
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