10. Acar starts from rest with a constant acceleration of 5m/s2 along a straight line .Find the distance travelled by it in the first 2 seconds and the distance travelled by it in the 2nd second.
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Explanation:
u=0
a=5m/s^2
t=2s
v=u+at
v=0+5*2
v=10m/s
S=u*t+1/2*a*t^2
S=0+1/2*5*2*2
S=10m
Now, t=4s
S=u*t+1/2*a*t^2
S=0+1/2*5*4*4
S=40m
Therefore, The distance travelled by it in first 2 seconds is 10m and next two seconds is 40m
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