Question

10. Among the following more dilute solution 1) 2M H,SO 2) 2m H,SO 3) 2N H,SO4 4) 0.98% H,SO 1. 6 moles of a solute is present in 100 m of a solution. The mole fraction of solu 1) 0.6 2) 0.06 3) 0.03 4) 0.9​

Answer 1

Answer:

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Explanation:

98% by weight of solution means 98g of H  

2

​

SO  

4

​

 is present in 100g of solution.

Volume of solution =  

density of solution

mass of solution

​

=  

(1.8×1000)g/L

100g

​

 

Volume of solution =  

18

1

​

L

Per cent  H  

2

​

SO  

4

​

 w/v of solution = molarity =  

volume of solution (in L)

number of moles of H  

2

​

SO  

4

​

 

​

 

Molarity =  

volume of solution

given mass of H  

2

​

SO  

4

​

/ molar mass of H  

2

​

SO  

4

​

 

​

 

Molarity =  

1/18

98/98

​

=18M

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