Question

10. An artificial satellite is moving in a circular orbit of radius
42250 km. Calculate its speed if it takes 24 hours to revolve
around the earth.​

Answer 1

Answer:

The speed of an object moving in a circular orbit is given by formula:

$\huge\bold\red{\mathfrak{v=\frac{2×\pi×r}{t}}}$

Given:

Radius ,r = 42250 km

Radius ,r = 42250 kmTime,t = 24 h

To Find:

Here,speed ,v= ?

Solution:

$\bold\red{\mathbb{v=\frac{2×\pi×r}{t}}}$

Now,putting the values in the above formula,we get:

$\huge\bold\blue{\mathbb{speed,v= \frac{2×22×42250}{7×24}}}$

$\boxed{\boxed{\boxed{\mathbb{v = 11065.4km/h}}}}$

We can convert this speed from kilometres per hour to kilometres per second by dividing it by the number of seconds in 1 hour (which is 60×60 s ).Thus:

$\bold\blue{\mathbb{v=\frac{11065.4}{60×60}}}$

$\boxed{\boxed{\boxed{\mathbb{v=3.07km/s}}}}$

________________________

Answer 2

Answer:

11055.41 km/hr

Explanation:

Given:

• Radius of the circular orbit = 42,250 km
• Time taken = 24 hours

To find:

• Speed of the artificial satellite

Speed = $\frac{Distance}{Time}$

Distance = circumference of the circular orbit

Circumference of the circular orbit = $2 \pi r$

Circumference of the circular orbit = $2 \times 3.14 \times 42250$

Circumference of the orbit = 265330 km

Time = 24 hours

Speed = $\frac{265330}{24}$

Speed =11055.41.. km/hr

The speed of the artificial satellite is equal to 11055.41 km/hr