Question

10. An electric heater working at 230V produces 1000J energy in one second
a)what is the power of the lamp?
b)calculate the resistance of the heating coil used in it?
c) calculate the heat produced in 5 minute​

Answer 1

Answer: 1000 W  52.87 Ω    300000 J

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Step-by-step explanation:

soln,

a) Power of heater = 1000J/s = 1000 W  as heater produces 1000J energy in one second.

b) Power (P) = I *V

or, 1000 = I * 230

i.e. I = 4.35 A

so, Resistance (R) = V/I = 230 / 4.35 = 52.87 Ω

c) heat produced (H)= P * t  where t is time taken = 5* 60 s

= 1000 * 5 * 60

=300000 J