Question

10. An iron sphere of mass 1kg is dropped from a height of 10m. If the acceleration of sphere is 9.8m/s²,
calculate the momentum transferred to the ground by the ball.​

Answer 1

Answer:

14 kgm/s

Explanation:

Momentum = mv

v^2 = u^2 + 2*a*s

v^2 = 0 + 2*9.8*10

v = √196 = 14

Momentum = mv = 1*14 = 14 kgm/s