10. An object of mass 2 kg is thrown vertically upwards with an initial velocity of 20m/s. What will be
its Potential energy at the end of 3 seconds ? (Assume g=10m/s2). (3)
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Answer :
- Potential energy = 2100 J
S O L U T I O N :
Given,
- Mass (m) = 2 kg
- Initial velocity (u) = 20 m/s
- Time (t) = 3 s
- Acceleration due to gravity (g) = 10 m/s²
To Find,
- The Potential energy of the object at the end of 3 seconds.
Explanation,
Applying 2nd equation of motion,
S = ut + 1/2 × at²
[ °.° s = h & a = g ]
=> h = ut + 1/2 × gt²
[ Put the values ]
=> h = 20 × 3 + 1/2 × 10 × (3)²
=> h = 60 + 5 × 9
=> h = 60 + 45
=> h = 105 m
Applying potential energy formula,
P.E = mgh
[ Put the values ]
=> U = 2 × 10 × 105
=> U = 20 × 105
=> U = 2100 J
Therefore,
The Potential energy of the object at the end of 3 seconds is 2100 J.
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