10 angle, which is four times its complement.
(i) Find the angles when two angles are supplementary and the
larger is 58° more than the smaller.
(ii) Two angles are supplementary and the larger is 40° less than three times the smaller, Find the
smaller angle.
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i) Let the angles be = x, y
x = y + 58
x + y = 180⁰ ( angles are supplementary)
y + 58 + y = 180
2y + 58 = 180
2y = 180 - 58
2y = 122
y = 122/2
y = 61⁰
x = 61 + 58 = 119
x = 119⁰ , y = 61⁰
ii) Let the angles be = x, y
x = 3y - 40
x + y = 180⁰ ( angles are supplementary)
3y - 40 + y = 180
4y - 40 = 180
4y = 180 + 40
4y = 220
y = 220/4
y = 55⁰
x = (3 × 55) - 40
x = 125⁰
x = 125⁰, y = 55⁰
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