10. Apply Kirchoff's laws of current electricity to
establish the condition of a balanced
Wheatstone's bridge.
Answers
Explanation:
Use of Kirchoff’s Law in Wheatstone Bridge
Kirchoff’s Law states that the algebraic sum of currents at a junction of an electric circuit is zero. The concept of the laws Current and resistance in a simple circuit can be determined by using Ohm’s law. But if the circuit is complex then Ohm’s law is not sufficient. For this reason, Kirchhoff’s two laws are used to calculate current and resistance in a complex circuit. Kirchhoff’s Laws for current and voltage lie at the heart of circuit analysis.
If four junctions are made due to the formation of a closed loop by connecting four resistors in series and if an electric cell is connected between the two opposite junctions and a galvanometer is connected between the other two opposite junctions then the circuit thus formed is called Wheatstone bridge.
Let us consider that four resistors P, Q, R, and S are arranged like tetrahedral ACDF. Wheatstone bridge is formed by connecting a battery B or an electric source, a plug key K and a variable resistor X between the junctions A and D and a galvanometer G between the junctions C and D
In this situation, the main current ‘i’ entering the network at A divides and flow through different resistors of the network and meet again at D. Whether current through the galvanometer will flow or not depends on the potentials at points C and F. If for the resistances the potentials at C and D are not equal, then current will flow through the galvanometer and the galvanometer will give some deflection. This situation is called unbalanced condition. But if the potentials at points C and F are equal, then no current flows through the galvanometer and the galvanometer shows no deflection. This condition is called balanced condition or null condition. By controlling different resistances in the circuit, the balanced condition is established.