10. Arithmetic mean of marks (out of 25) scored by 10 students was 15. One of the student
named Karishma enquired the other 9 students and find the deviations from her marks are
noted as - 8. - 6. – 3. – 1,0.2.3.4.6. Find Karishma's marks
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Answer:
Let Krishna's marks be x marks.
x
ˉ
=15
n=10
∑x=x+x−8+x−6+x−3+x−1+x+x+2+x+3+x+4+x+6=10x−3
15=
10
10x−3
150+3=10x
x=
10
153
=15.3 marks.
∴ Krishna scored 15.3 marks
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