Question

10 boys are arranged at random along a circle the probability of arranging them so that to specified bus of those 10 must come together is​

Answer 1

probability of arranging Boys so that two specified boys of those 10 must come together = 2/9

Step-by-step explanation:

Correct Question is

10 boys are arranged at random along a circle the probability of arranging them so that two specified boys of those 10 must come together is​

Arrangement of 10 boys in circle = (10 - 1) ! = 9 !

Now taking 2 Specified boys as One group   &  Remaining 8

8  + 1 (group of two boys) = 9  Can be arranged in

(9 - 1) = 8! Ways

2 Boys in group can be arranged in 2 Ways

Arrangement such that two boys Come together = 8! * 2

Probability  =  8! * 2  / 9 !

= 2 / 9

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