10 c.c of a mixture C2H4 and C2H2 is completely burned with 33 c.c O2 and cooled to room temperature. On passing through KOH the volume of gaseous mixture reduces to 5 c.c. The volume of C2H4 in the original mixture is? JEE ADVANCED CHEMISTRY
Answers
Answered by
0
Answer:
Let the original mixture contains x ml of CO and (40-x) ml of C
2
H
2
.
Th balanced chemical equations are as shown below.
40−x
C
2
H
2
+
2.5(40−x)
2
5
O
2
→
2(40−x)
2CO
2
+H
2
O(l)
x
C
O+
0.5x
2
1
O
2
→
x
CO
2
Total volume is 104 ml.
Hence, 2(40−x)+x+(100−2.5(40−x)−0.5x=104.
On solving this, we get x=24 ml.
Hence, the volumes of CO and C
2
H
2
are 24 ml and 40−24=16 ml respectively.
Answered by
2
Answer:
Let the original mixture contains x ml of
Th balanced chemical equations are as shown below.
40−x
Similar questions