10. Calculate the maximum work when 24
g of 0, are expanded isothermally and
reversibly from the pressure of 1.6 bar to 1
bar at 298 K.
Ans. : (-873.4 J)
Answers
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Howdy friend your answer is
Solution:-
Given weight =24g
Molecular weight =32g
No. of moles (n)=
32
24
=0.75 mol
As we know that work done in an isothermal process is given as-
W=−2.303
P
2
P
1
Given:-
T=298K
P
1
=1.6×10
5
Pa=160kPa
P
2
=100kPa
Therefore,
W=−2.303×0.75×0.0821×298×log
100
160
⇒W=−42.26×log1.6=−8.62atm−L
JK its -873.4 J. or is it?
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