Question

10. Calculate the maximum work when 24
g of 0, are expanded isothermally and
reversibly from the pressure of 1.6 bar to 1
bar at 298 K.
Ans. : (-873.4 J)​

Answer 1

Howdy friend your answer is

Solution:-

Given weight =24g

Molecular weight =32g

No. of moles (n)=

32

24

​

=0.75 mol

As we know that work done in an isothermal process is given as-

W=−2.303

P

2

​

P

1

​

​

Given:-

T=298K

P

1

​

=1.6×10

5

Pa=160kPa

P

2

​

=100kPa

Therefore,

W=−2.303×0.75×0.0821×298×log

100

160

​

⇒W=−42.26×log1.6=−8.62atm−L

JK its -873.4 J. or is it?