10. Car P started driving north from X at 7:00 a.m. Car Q started driving north from X at 10:00 a.m. The ratio of the speeds of P and Q is 3:4. Find their meeting time. (A) 7:00 p.m. (B) 12:15 p.m. (C) 6:00 p.m (D) 10:00 p.m
Answers
Answered by
8
Answer:
Given speeds are in the ratio 3:4
so consider the speeds be 30 and 40
S T = D
30 4 = 120
40 3 = 120
so we can write this as 120/40-30 =12 hrs
7:00 PM
Answered by
3
Answer: (A) 7:00 p.m.
Step-by-step explanation:
- For the two cars to meet at one point the distance covered by them must be equal.
- The ratio of the speeds given is 3:4.
- Let the time taken by car P be t hrs.
- Distance covered by car P= 3t Km
- Distance covered by car Q= 4(t-3) Km
- According to question,
4(t-3)=3t
⇒4t - 12=3t
⇒4t-3t=12
∴ t=12 hrs.
- Hence, they will meet at 7:00 p.m. after 12 hrs.
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