Question

10. CASE STUDY PROBLEM. In a
school, buses are hired to take
the students of std X on a field
trip. There are 156 , 208 and
260 students in groups A,B and
C respectively. Minimum
number of buses are to be
hired for this purpose. Same
number of students should be
accommodated in each bus to
be arranged for the separate groups. if group C will not be taken along and 26 students of group A refused to join, then the minimum number of buses required to accommodate remaining students is ..​

Answer 1

Answer:

You should take H.C.F. of 156, 208 and 260.

=> HCF of 156 and 208

P.F. of 156 = 2×2×3×13

P.F. of 208 = 2×2×2×2×13

Therefore, H.C.F. of 156 and 208 = 2×2×13 = 52

=> Now , H.C.F. of 52 and 260

P.F. of 52 = 2×2×13

P.F. of 260 = 2×2×5×13

H.C.F. = 2×2×13 = 52

●Max. number of students per bus = 52

●Total number of students = 156+208+260 = 624 students.

●No. of buses = 624/52 = 12 buses.

Step-by-step explanation: