Question

10 cc of h2o2 solution when reacted with ki solution produced 0.5 g of iodine. calculate the percentage purity of h2o2
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Answer 1

Answer:

First, we have to create the equation of the reaction between H2O2 and I2: H2O2 + 2I- --> 2OH- + I2

So basically 1 mol of I2 is formed by the reaction of 1 mol of H2O2 with I-.

First we find the number of moles of I2: 0.500/(126.9x2) = 0.00197 mol

Therefore we can conclude that the number of moles of H2O2 reacted is also 0.00197 mol.

However, since they are asking for the percentage purity of H2O2, and your question looks like it lacks some parameters, it is not possible to find the % purity of H2O2. But given the above information, we can conclude that the mass of H2O2 is 0.00197x(16+16+1.008+1.008) which is 0.067g. If it is a 10cc H2O2 solution, then the concentration of the solution (by mass) would be 0.067/0.01 = 6.7g/dm^3, and the concentration by mol is 0.00197/0.01 = 0.197mol/dm^3

Explanation:

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