Question

10. Charges of -10.-10. -15 ssd -30 C are placed in
order at each of the corners of a square of 10 cm side.
Calculate the potential at the point of intersection of
the diagonals
​

Answer 1

Answer:

-8.273 × 10^11 V

Explanation:

given

charges at each point q1(-10), q2(-10), q3(-15) and q4(-30) at each corners of a square

side of given square = 10cm = 10*10^-2 m = 0.1m

the potential at the center of the intersection is given by

V = 1/$4 \pi$ε₀ [ q1\r + q2\r +q3\r + q4\r]

where,

r = distance of each charge from the point of intersection of diagonals =

1\2$\sqrt{.1^{2} +.1^{2} }$ = .07071 m

therefore

V= 1\$4 \pi$ε₀(1\.07071) [ -10+ -10 + -15+ -30]

taking the r=.07071 as the common term

V = 9 × 10^9 ×(-65)×(1\0.7071)

V = -8.73 × 10^11 V