Question

10. Check whether 4^n can end with the digit 0 for any rational number n.​

Answer 1

Answer:

no

Step-by-step explanation:

prime factoriztion of (4)^n

=(2*2)^n

for any number to end in 0, there should be a 5 and a 2 in the prime factorization. as per fundamental theorem of arithmetic, the prime factorization of 4 is unique which doesn't cary a 5.

hence, there is no 'n' for which 4^n can end with 0.

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Answer 2

Answer:

No

Step-by-step explanation:

No, because factors of

$4 ^{n} is \: (2 \times 2) ^{n} \:$

in it's factor 5 is not present.

So, 4^n can never end with digit zero....

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