10.Convert -30°C into (a)kelvin (b)°F
[(a) 243K (b) 22°F]
Answers
Answered by
4
22400 ml. of oxygen at 273 K temperature and 3-atm pressure = 22400 ×3/1= 67200 ml at STP.
So 224 ml of oxygen at 273 K and 3-atm = 224 ×3= 672 ml at STP
The number of Oxygen molecules present in 22400 ml of gas at STP=N
(where N= Avagadro Number)
Therefore 224 ml of oxygen at 273K and 3-atm pressure will contain =N×672/22400 × N molecules.
=3/100×6.022×10
23
=18.066×10
21
Molecules =1.8066×10
22
molecules
hope it helps you
Answered by
0
Answer:
a) 30°c b) 251°c
Explanation:
243K - 273
=30 ° c
b) 273-22
=251
Similar questions