Math, asked by ashishar5015, 18 days ago

10 cubes each of edge 1 cm long are placed together. Find the total surface area of the cuboid so formed

Answers

Answered by tennetiraj86
32

Step-by-step explanation:

Solution :-

Given that

Edge of a cube = 1 cm

Number of cubes are given = 10

If 10 cubes of each 1 cm are placed together i.e. they are joined end to end then the resultant solid is a cuboid.

Length of the cuboid (l) = 10 cm

Since length = 10× edge of cube = 10×1 = 10 cm

Breadth of the cuboid (b) = 1 cm

Height of the cuboid (h) = 1 cm

We know that

Total surface area of a cuboid

TSA = 2(lb+bh+hl) sq.units

Total Surface Area of the given cuboid

= 2[(10×1)+(1×1)+(1×10)] cm²

= 2(10+1+10) cm²

= 2(21) cm²

= 42 cm²

Total Surface Area = 42 cm²

Answer:-

Total Surface Area of the resultant cuboid is 42 cm²

Used formulae:-

→ Total surface area of a cuboid

TSA = 2(lb+bh+hl) sq.units

  • l = length
  • b = breadth
  • h = height

Used Concept :-

→ If cubes are joined by end to end then the resultant solid is cuboid .

Answered by afrinaa3368
9

Answer:42cm²

Step-by-step explanation:tsa of cuboid = 2(lb + bh + hl )

L = 10×1 =10

B = 1

H = 1

Tsa = 2( 10 × 1 + 1 × 1 + 10 × 1 )

= 2( 10 + 1 + 10 )

= 2 × 21

= 42cm²

I hope it help you

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