Question

10: Divide 26000 into two parts, so that simple interest on the first part for 2 years at 6% p.a.
may be equal to the simple interest on the second part for 3 years at 8% p.a.
Let the first part be and the​

Answer 1

Answer:Let one part is x and other part is (6000−x)

Now,

S.I on first part =S.I. on second part  

x×  

100

12

​  

×  

12

9

​  

=(6000−x)×  

100

10

​  

×  

2

3

​  

 

∴x=3750

and (6000−x)

       ⇒6000−3750=2250

Therefore two parts of 6000 are 3750 and 2250.