Question

10 dm^3 of oxygen is contained in a vessel at pressure of 20 Atms. If another evaluated vessel of similar capacity is connected to it, calculate the pressure of gas in both the vessels​

Answer 1

Explanation:

v1= 10dm, P1=20atm, V2 =10+10=20dm , P2=?

BOYLE'S LAW

P1 V1= P2 V2

20×10÷20

= 10 ans

Answer 2

Answer:

The final pressure in both vessels will be 10 atm.

Explanation:

You are correct. The Ideal gas law states that PV = nRT, where n is the number of moles, R is the ideal gas constant, and T is the temperature. In this case, we know that n and T are constant, so the pressure and volume are inversely proportional.

If we have an initial volume of 10 dm3 and an initial pressure of 20 atm, and we connect another vessel of similar capacity, so the final volume becomes 20 dm3. Since the number of moles and temperature are constant, the pressure will decrease in proportion to the increase in volume.

So, using the Ideal gas law, P1V1 = P2V2

2010 = P220

P2 = 20*10/20 = 10 atm.

Therefore, the final pressure in both vessels will be 10 atm.

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